MNOOH can be reduced to MN2 by adding a reducing agent such as hydrogen gas or carbon monoxide in the presence of heat. The reducing agent will donate electrons to the manganese in MNOOH, causing it to lose oxygen atoms and form MN2. This process is known as reduction and is commonly used in chemical reactions to convert metal oxides to pure metals. **

The atomic number of MnO4 is 25, as manganese (Mn) has an atomic number of 25 and there are four oxygen atoms in the compound. The atomic number of Mn2 is also 25, as there are two manganese atoms in the compound. **

The ordinal number of MnO4 is manganese (VII) oxide, as manganese has a +7 oxidation state in this compound. The ordinal number of Mn2 is manganese (II), as manganese has a +2 oxidation state in this compound. These ordinal numbers indicate the oxidation state of manganese in each compound. **

The redox equation for the reaction of HCOOH (formic acid) with MnO4- to form CO2 and Mn2+ is as follows: 2HCOOH + 2MnO4- + 3H2O → 2CO2 + 2Mn2+ + 5O2 + 6H+ In this reaction, formic acid is oxidized to carbon dioxide, while permanganate is reduced to manganese(II) ions. This is a redox reaction because there is a transfer of electrons from formic acid to permanganate. **

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When an aqueous solution of Mn2+ cations is mixed with ammonia solution, I would expect the formation of a precipitate of manganese hydroxide, Mn(OH)2. This is because ammonia is a weak base and can react with the Mn2+ cations to form an insoluble hydroxide precipitate. The balanced chemical equation for this reaction is: Mn2+ (aq) + 2NH3 (aq) + 2H2O (l) → Mn(OH)2 (s) + 2NH4+ (aq) The manganese hydroxide precipitate will appear as a solid in the solution, indicating the formation of the product. **